1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | -- MariaDB 10.4 에서 테스트 했습니다. -- WITH t AS ( SELECT 1170 u, 'test3333' room_id, null parent_u, 'aa' custom_u UNION ALL SELECT 1171, 'test3333' , null , 'bb' UNION ALL SELECT 1173, 'test3333' , null , 'cc' UNION ALL SELECT 1174, 'test3333' , null , 'dd' UNION ALL SELECT 1175, 'test3333' , null , 'ee' UNION ALL SELECT 1176, 'test3333' , 'bb' , null ) SELECT a.u , a.room_id , a.parent_u , a.custom_u , b.u FROM t a LEFT OUTER JOIN t b ON a.parent_u = b.custom_u AND a.room_id = b.room_id -- 조인조건 WHERE a.room_id = 'test3333' -- 검색조건 ORDER BY IFNULL(b.u, a.u), a.parent_u ; |